**PPS**

Here is a way of solving the task algebraically:##### You might like to consider a more general version of the task, eg change the multiplier 1.2 to *r*, change the coordinates of B to (*b*, 0).

We can use Pythagoras' rule to express the distances AP and BP in terms of *x*, *y* and *a*.

This gives us two equations that allows us to eliminate *a* and to form a single equation in *x* and *y*.

The equation can be reduced to the form shown below:

this means that P(*x*, *y*) lies on a circle with centre (72/11, 0) and radius 12x5รท11.

FREE:

a high-res pdf file of this new GEOaa-zz task

a high-res pdf file of this new GEOaa-zz task